Enter a radius, diameter, circumference, or a known area — get the area from A = πr², in any unit, with every other circle measure and a full step-by-step solution.
Enter the measure you know — the area and every other figure update as you type.
Uses full-precision π
The area of a circle is the amount of flat space it covers. It depends only on the distance from the centre to the edge — the radius. There is one formula that does all the work, and a couple of identities for when you are handed a different measure instead.
Three steps when you start from the radius. If you start from the diameter or circumference, add one short step at the front to find r.
If you already have r, skip ahead. From a diameter, halve it; from a circumference, divide by 2π.
Multiply the radius by itself. Squaring is why area grows so fast — double r and this number quadruples.
Multiply that square by π. The result is the area, in the square of whatever unit you measured in.
The same circle (radius 5), reached three ways. Whatever you are given, you end at the same area.
You don't always have to find the radius first. Each known quantity has a direct formula that folds the conversion in.
Circle area is everywhere a round thing meets a quantity — material, coverage, flow, or price per square inch.
The fast lookup for “area of a circle with radius X” and “with diameter X”. Each cell shows the area in square units, plus the exact multiple of π.
A few properties make circle area quicker to reason about — and harder to get wrong.
Almost every wrong answer traces back to one of these three slips.

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. This guide shows how to find the equation from a graph, two points, or a point and slope, graph it, and convert standard form.

The volume of a cylinder is V = πr²h, where r is the radius of the circular base, h is the height, and π ≈ 3.14159. This guide shows why the formula works, walks through a full numerical example, and covers diameter inputs and unit conversions.

The distance between two points is d = √((x₂−x₁)² + (y₂−y₁)²). It comes straight from the Pythagorean theorem: the horizontal and vertical gaps between the points are the two legs of a right triangle, and the distance is the hypotenuse.